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Exercise 1. So, it can be written in the form of 2m. Case I : n is even, i. Hence, we can conclude from above two cases that if n is odd, then n 2 � 1 is divisible by 8. Question oslution The largest number which divides 70 andleaving remainders 5 and 8, respectively, is A 13 B 65 C D Solution: A Since 5 and 8 are the remainders of 70 andrespectively.
Question 8 The product of a non-zero rational and an irrational number dlass A always irrational B always rational C rational or irrational D one Solution: A Product of a non-zero rational and an irrational number is always irrational.
Justify your answer. Solution: No. Is this statement true or false? Give reasons. So, one integer out of ncert exemplar class 10 maths ch 10 solution two must be divisible by 2. Hence, product ncert exemplar class 10 maths ch 10 solution two consecutive integers is divisible by 2. So, one integer of these three must be divisible by 2 and another solutoon must clsss divisible by 3.
Hence, product of three consecutive integers is divisible by 6. Question 6 The numbers and are solition divisible only by 3, 5, 15, 25 and What is HCF?
The highest common factor among these is Hence, it is a composite number. Give reasons for your answer. Solution: After simplification denominator bcert factor 5 3. 01, this is terminating decimal. Question 10 A rational number in its decimal expansion is Solution: So, it represents a rational number and also its denominator must have the form 2 m x 5 n.
Thus, Solution: Let a bean arbitrary positive integer. Solution: Let a be an arbitrary positive integer. Question 6 If n is an odd integer, then show that n 2 � 1 is divisible by 8. From eq. Solution: Since, 1, 2 and 3 are the remainders ofandrespectively. Question 11 Show that 12 n cannot end with the digit 0 or soultion for any natural number n. Solution: If any number ends with the digit 0 or 5, it is always divisible ncert exemplar class 10 maths ch 10 solution 01.
If 12 n ends with the digit zero or five it must be solktion by 5. This is possible only if prime factorisation of 12 n contains the prime number 5. Question 12 On a morning walk, three persons step off together and their steps measure 40 cm, 42 cm and 45 cm, respectively. What is the minimum distance each should walk so that each can cover the same distance in complete steps?
Solution: We have to lind the LCM of 40 cm, 42 cm and 45 cm to get the required minimum distance. Hence, write its decimal expansion, without actual division. Hence, 0. Solution: On dividing n by 3, let q be the quotient and r be the remainder.
So, in this exenplar, only n is divisible by 3. Question 3 Prove that one of any three consecutive positive integers must be divisible by 3. On dividing n by 3, cb q be the quotient and r be Ncert Exemplar Class 10 Maths Solutions Ch 8 Office the remainder. Hence, one of any three consecutive positive integers must be divisible by 3. Question 4 For any positive integer n, prove that n � n is divisible by 6. So, one out of these must be divisible by 2 and another one must be divisible by 3.
Therefore, a is divisible by both 2 and 3. Solution: On dividing n by 5, let q be the quotient and r be the remainder. RD Sharma Class 12 Solutions. Watch Youtube Videos.
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