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JEE Main Maths Limits, Continuity and Differentiability Previous Year Questions With Solutions. lim ? h > 0 2 (a + h) sin ? (a + h) + (a + h) 2 cos ? (a + h) 1. = 2 a sin ? a + a 2 cos Byjus Maths Limits 500 ? a. Hence, the limit doesn�t exist. = lim ? x > 0 (1 + tan ? x 1 ? tan ? x) 1 / x = lim ? x > 0 { (1 + tan ? x) 1 / tan ? x } (tan ? x) / x { (1 ? tan ? x) 1 / tan ? x } (tan ? x) / x = e e ? 1 = e myboat091 boatplansted Reading Time: 2 mins. 2. Evaluate the Given limit: Solution: Given limit: Substituting x = ?, we get = (? � 22 / 7) 3. Evaluate the Given limit: Solution: Given limit: Substituting r = 1, we get = ?(1) 2 = ?. 4. Evaluate the Given limit: Solution: Given limit: Substituting x = 4, we get = [4(4) + 3] / (4 � 2) = (16 + 3) / 2 = 19 / 2. 5. Evaluate the Given limit: Solution: Given limit. RD Sharma Class 11 Maths Chapter 29 Limits Exercise Author: BYJU'S Subject: RD Sharma Class 11 Maths Chapter 29 Limits Exercise Keywords: RD Sharma Class 11 Maths Chapter 29 Limits Exercise Created Date: 4/7/ PM.
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