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Upstream & Downstream Word Problems - Distance Rate Time.� Time and Work Problems - Shortcuts and Tricks. The Organic Chemistry Tutor. Upstream and Down Stream Problems. ExampleDefinitionsFormulaes. 20,+.� When the boat starts moving upstream a float was dropped from it. The boat travels km up stream turned about and caught up with the float. The time is taken by the boat to reach the float is. Distance Problem - Upstream/Downstream/Current Speed. This topic has expert replies. Post new topic Post Reply.� The same steamer going downstream would cover the distance between the towns in 3 hours. How long would it take a raft moving at the speed of the current to float from town B to town A? A)10 hours B)12 hours C)15 hours D)18 hours E)20 hours. OA is D. I was way off on this one. I think I may have bombed it coz I'm not too clear what direction the rafter would float (upstream or downstream).� Again wow! You know math is truly amazing and I wish I had my present attitude when I was a kid. I'd just look at problems and say 'it's hard'. So my mistake was an incorrect/simplistic assumption of the speed of the current. Looking at the 2 equations you set up: B+C=6 B-C=4.

In my many years I have come to a conclusion that one useless man is a shame, two is a law firm, and three or more is a congress. Recently, I was reading about stadiametric range finding methods being used by hunters and their telescopic sights � I was surprised to find a lot of writing on the topic.

I will review these methods here. My interest in these methods comes from my addiction to a video game, Silent Hunter, which is an excellent simulation of submarine warfare during WW2. Periscopes contain a built-in stadimeter Figure 1 that was used to measure the angular height of a target ship. If the target ship's height could be obtained from nautical reference manuals, the range to the target ship could be computed using the formula.

The following Youtube video Figure 2 does a nice job of reviewing the calculation mechanics of stadiametric range determination using a telescopic sight. However, it does not derive the formulas that are used. I will derive these formulas in the Analysis portion of this post.

As an engineer, I view all three methods as variations on the same theme. However, the topic is a subject for some debate because stadiametric ranging using these sights is one of the few areas where people still routinely do arithmetic in their head.

If you are a person who likes to work with inches, the arithmetic may be simpler for the MOA and IOA methods because of some useful measurement coincidences. If you work in the metric system, you may find the milliradian approach has simpler math.

It all depends on how your brain is wired. The milliradian mil is an approach that can be used regardless of the unit of measure. It is based on the use of radian unit, which is the standard unit of angular measure in the mathematical world. Figure 3 shows how to derive the distance subtended by one mil at yards and the range at which 1 inch is subtended by a mil. On a personal note, the mil is actually the first unit of angular measure that I learned as boy.

My dad was an old US Army artilleryman and he liked to use these units. Don't get me started on the differences between the different definitions of mil � so many definitions and so little difference. We can determine the range of a inch target with a circular measure of 1. Figure 5 shows that a minute of angle subtends an arc of 1.

Most people approximate both of these relationships as 1 inch at yards. For accurate ranging at long distance, you need to account for the 4.

Figure 5: Derivation of Minute of Angle Relationships. To illustrate how to use a telescopic sight with minute-of-angle graduations, consider the case where we have a inch objects that subtends 1. We can compute the range of this object as shown in Figure 6. In actual fact, you can define a circular angle in any number of ways. A small number of telescopic sights define the circular angle in terms of the angle subtended by 1 inch at yards Figure 7.

This makes the math very simple for those who like to think in terms of inches. I will again work an example Figure 8 that assumes a inch target but that now subtends 1. I was amazed at the number of forum posts on this topic that I encountered.

At a fundamental level, these approaches are all mathematically equivalent. It really comes down to what is more comfortable for the individual. The mil-radian approach is unit-independent and that has its attractions.

I am unclear as to why anyone would want to use the true MOA approach, however, some reticles are not available in the IOA format and you may have no choice. I recently was asked to explain how a Fiber-To-The-Premises FTTP system measures the length of fiber between the central office and each residence in the network Figure 1.

This is an interesting question and I thought it would be worthwhile to the describe the measurement process here. Service providers are interested in the length of their fiber runs because this information is useful in maintaining their fiber optic infrastructure. For example, a common maintenance situation would involve a home where the data service has become unreliable and the service degradation needs to be investigated. My first questions in these cases are 1 how much total signal attenuation is on the fiber, and 2 how long is the fiber run to the residence.

I ask these two questions because the most common issue that I uncover is too much attenuation or distance on the fiber, which is usually caused by. These are, by far, the most commonly encountered problems.

One common scenario involves a backhoe accidentally cutting a fiber, which means a new fiber must be spliced in. These repairs are often difficult to make cleanly. There are dispersion-induced distortions that will occur in analog system. Low-levels of dispersion will behave like excess fiber loss.

There can be many other sources of trouble, but I begin my troubleshooting by looking for excessive attenuation or fiber length � these are the most common sources of trouble, and they are usually easy to find. This means that the ONTs can "pick off" the portion of the data stream that it has been assigned as all the data comes to it.

This means that the ONTs must transmit at a time chosen to compensate for the transmission time differences caused by the distance variations.

This post is about how this compensation value is chosen. Most engineering calculations have a "bookkeeping" aspect to them and determining the length of a fiber optic cable is no exception. Equation 1 is the key relationship, which basically says that distance equals rate speed of light multiplied by time.

Figure 2 shows the delays that make up the round-trip time, which is what the CO can measure. Figure 2: Delays that must be accounted for. The parenthetical term in the highlighted equation is the flight time. Figure 4: Calculate the Speed of Light on the Fiber. Figure 5: Fiber Length Calculation Example.

This question has come up before and it is now time to write down the answer in detail. It provides a nice illustration of the myriad bookkeeping details associated with what is a very simple concept. The discussion above uses my notation. Here is an excerpt from the GPON specification that gives the official formula. It is the same formula, just notationally different. Figure 7: Effective Fiber Index of Refraction. Figure 7 is from this Corning document. The whole point of being a citizen soldier is that you cannot wait until you are no longer a soldier.

When I was a boy, most of the fathers in my neighborhood had served in WW2. One of these fathers, Alvin Weese, was an Army veteran who was very specific about his WW2 service by saying that he had "served under Patton " and you could clearly see his pride in having been a soldier in Patton's 3 rd Army. This weekend, I saw a Youtube video by a gentleman , with the handle "The Chieftain", who works for wargaming.

While he addressed each of the concerns that I listed above, in this post I will limit my focus to his statement that the sloped frontal armor on the M4 Sherman was actually comparable to the unsloped frontal armor of a Tiger I. Specifically, he states that the Sherman had an equivalent frontal armor thickness of 3. Since the Sherman is listed as having 2 inches of frontal armor, I thought it would be interesting to examine his statement more closely to understand the reasoning behind the 3.

In response to an excellent response from a reader of my blog, I will also look at how the armor was constructed and how a Sherman's armor had a much more difficult attack to resist than the Tiger I did. We can thank the gaming community for bringing so many of these facts about WW2 weapons into light. Figure 2 shows the Youtube video that got me thinking.

The lecturer does an exceptional job describing the complex managerial context of US armored forces during WW2. Evaluating armor protection is complex process. Years ago, I spent some time reading articles on how battleship armor was designed see the excellent work by Okun.

I now see that designing tank armor is just as difficult as designing battleship armor. The two main reasons for sloping armor Upstream And Downstream Problems Labs are two 1 increase its effective thickness, and 2 increase the likelihood of causing incoming rounds to glance off.

An assumption of this discussion is that armor can be compared strictly on a thickness basis. Like all interesting engineering questions, the answer is "it depends. There are numerous ways to build armor.

Tiger I used RHA. A Sherman tank's armor had to fend off attack from a high-velocity 88 mm gun, while the Tiger I had to resist attack from a low-velocity 75 mm. For a Sherman to provide levels of crew protection comparable to what a Tiger I provided, the Sherman would have needed much more armor. As I read the various articles about the Sherman, you see that its characteristics were more suited to some battlefields than others.

The Chieftain said that Sherman's frontal armor is usually listed as 2 inches thick, while the frontal armor of a Tiger I Figure 3 is usually listed a mm 4 inches thick. According to The Chieftain, this means that the M4 Sherman's effective armor thickness is really Problems Related To Upstream And Downstream 3. Figure 4 shows how The Chieftain got his answer of 3. The key formula here is. Unfortunately, the M4 Sherman did not use sloped armor for its sides, but at least the frontal armor was sloped, thus making more effective use of the 2 inch frontal armor plate.

While I am very familiar with the sloped armor on the T34 and Panther tanks, I had never thought about the M4 Sherman's armor being sloped. The Sherman's sloped armor had significant advantages when facing opponents armed with 50 mm or 57 mm main guns e.

PzKpfw III. However, these advantages vanished when faced with opponents armed with 75 mm or 88 mm main guns e.

Panther and Tiger I because of armor overmatch, which occurs when the shell diameter is greater than the armor thickness. When armor is overmatched, the slope plays minimal role.

For a good description of how overmatch affects the level of armor protection, see Appendix A.

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