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08.12.2020Author: admin

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Distance: Nearest first. Distance: Farthest first. Length: Shortest first. Since the two vectors to be added - the southward plane velocity and the westward wind velocity - are at right angles to each other, the Pythagorean theorem can be used.

This is illustrated in the diagram below. In this situation of a side wind, the southward vector can be added to the westward vector using the usual methods of vector addition.

The magnitude of the resultant velocity is determined using Pythagorean theorem. The algebraic steps are as follows:. The direction of the resulting velocity can be determined using a trigonometric function.

Since the plane velocity and the wind velocity form a right triangle when added together in head-to-tail fashion, the angle between the resultant vector and the southward vector can be determined using the sine, cosine, or tangent functions.

The tangent function can be used; this is shown below:. If the resultant velocity of the plane makes a Like any vector, the resultant's direction is measured as a counterclockwise angle of rotation from due East. The effect of the wind upon the plane is similar to the effect of the river current upon the motorboat.

If a motorboat were to head straight across a river that is, if the boat were to point its bow straight towards the other side , it would not reach the shore directly across from its starting point. The river current influences the motion of the boat and carries it downstream. The resultant velocity of the motorboat can be determined in the same manner as was done for the plane.

The resultant velocity of the boat is the vector sum of the boat velocity and the river velocity. Since the boat heads straight across the river and since the current is always directed straight downstream, the two vectors are at right angles to each other. Thus, the Pythagorean theorem can be used to determine the resultant velocity.

What would be the resultant velocity of the motorboat i. The magnitude of the resultant can be found as follows:. The direction of the resultant is the counterclockwise angle of rotation that the resultant vector makes with due East.

This angle can be determined using a trigonometric function as shown below. Motorboat problems such as these are typically accompanied by three separate questions:.

The first of these three questions was answered above; the resultant velocity of the boat can be determined using the Pythagorean theorem magnitude and a trigonometric function direction.

The second and third of these questions can be answered using the average speed equation and a lot of logic. The solution to the first question has already been shown in the above discussion.

We will start in on the second question. The river is meters wide. That is, the distance from shore to shore as measured River Boat Problems Byjus straight across the river is 80 meters. The time to cross this meter wide river can be determined by rearranging and substituting into the average speed equation.

The distance of 80 m can be substituted into the numerator. But what about the denominator? What value should be used for average speed? With what average speed is the boat traversing the 80 meter wide river?

Most students want to use the resultant velocity in the equation since that is the actual velocity of the boat with respect to the shore. And the diagonal distance across the river is not known in this case. If one knew the distance C in the diagram below, then the average speed C could be used to calculate the time to reach the opposite shore. Similarly, if one knew the distance B in the diagram below, then the average speed B could be used to calculate the time to reach the opposite shore.

And finally, if one knew the distance A in the diagram below, then the average speed A could be used to calculate the time to reach the opposite shore. It requires 20 s for the boat to travel across the river. During this 20 s of crossing the river, the boat also drifts downstream. Part c of the problem asks "What distance downstream does the boat reach the opposite shore?

And once more, the question arises, which one of the three average speed values must be used in the equation to calculate the distance downstream? The distance downstream corresponds to Distance B on the above diagram.

The speed at which the boat covers this distance corresponds to Average Speed B on the diagram above i. The mathematics of the above problem is no more difficult than dividing or multiplying two numerical quantities by each other.

The mathematics is easy! The difficulty of the problem is conceptual in nature; the difficulty lies in deciding which numbers to use in the equations. That decision emerges from one's conceptual understanding or unfortunately, one's misunderstanding of the complex motion that is occurring. The motion of the riverboat can be divided into two simultaneous parts - a motion in the direction straight across the river and a motion in the downstream direction.

These two parts or components of the motion occur simultaneously for the same time duration which was 20 seconds in the above problem. The decision as to which velocity value or distance value to use in the equation must be consistent with the diagram above. The boat's motor is what carries the boat across the river the Distance A ; and so any calculation involving the Distance A must involve the speed value labeled as Speed A the boat speed relative to the water.




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