Class 10 Maths Ch Triangles 90,Ncert Solutions Class 10th Exercise 12.3 Word,Aluminum V Bottom Fishing Boats Up,Ncert 10th Result 2019 Excel - Step 1
Question 1. Then, A BD. Question 2. The lengths of the diagonals of a rhombus are 16 cm and 12 cm. Then, the length of the side of the rhombus is A 9 cm B 10 cm C 8 cm D 20 cm Solution: B We know that the diagonals of a rhombus are perpendicular bisectors of each other.
Question 3. FD B AB. DE C BC. EF D BC. Question 4. Question 5. Question 6. Question 7. Question 8. Question 9. Question Is the triangle with sides 25 cm, 5 cm and 24 cm a right triangle? Give reasons for your answer. Solution: False We know that, if two triangles are similar, then their corresponding angles are equal.
Is the following statement true? Solution: False Two quadrilaterals are similar if their corresponding angles are equal and corresponding sides must also be proportional. Two sides and the perimeter of one triangle are respectively three times the corresponding sides and the perimeter of the other triangle. Are the two triangles similar? Solution: True Here, the corresponding two sides and the perimeters of two triangles are proportional, then the third side of both triangles will also in proportion.
If in two right triangles, one of the acute angles of one triangle is equal to an acute angle of the other triangle, can you say that the two triangles will be similar?
Is it true to say that if in two triangles, an angle of one triangle is equal to an angle of another triangle and two sides of one triangle are proportional to the two sides of the other triangle, then the triangles are similar? Solution: False Because, according to SAS similarity criterion, if one angle of a triangle is equal to an angle of the other triangle and the sides including these angles are proportional, then the two triangles are similar.
Here, one angle and two sides of two triangles are equal but these sides not including equal angle, so given statement is not correct. AP Hence proved. Find the altitude of an equilateral triangle of side 8 cm. Solution: Let ABC be an equilateral triangle of side 8 cm i. Then, D is the mid-point of BC. Corresponding sides of two similar triangles are in the ratio of 2 : 3. If the area of the smaller triangle is 48 cm 2 , find the area of the larger triangle.
If PN. Areas of two similar triangles are 36 cm 2 and cm 2. If the length of a side of the larger triangle is 20 cm, find the length of the corresponding side of the smaller triangle. A 15 metres high tower casts a shadow 24 metres long at a certain time and at the same time, a telephone pole casts a shadow 16 metres long. Find the height of the telephone pole. Hence, the height of the point on the wall where the top of the ladder reaches is 8 m.
Foot of a 10 m long ladder leaning against a vertical wall is 6 m away from the base of the wall. Find the height of the point on the wall where the top of the ladder reaches. The top of the ladder reached to A and distance of ladder from the base of the wall BC is 6 m. Find the lengths of the remaining sides of the triangles. Prove that if a line is drawn parallel to one side of a triangle to intersect the other two sides, then the two sides are divided in the same ratio. To prove : DE divides the two sides in the same ratio.
Also AB PS. Hence proved. A 5 m long ladder is placed leaning towards a vertical wall such that it reaches the wall at a point 4 m high. If the foot of the ladder is moved 1. It is proposed to construct a 26 km highway which directly connects the two cities A and B. Find how much distance will be saved in reaching city B from city A after the construction of the highway.
A flag pole 18 m high casts a shadow 9. Find the distance of the top of the pole from the far end of the shadow. The distance of the top of the pole, C from the far end i. A street light bulb is fixed on a pole 6 m above the level of the street. If a woman of height 1. Let distance between pole and woman be x m. Prove that the area of the semicircle drawn on the hypotenuse of a right angled triangle is equal to the sum of the areas of the semicircles drawn on the other two sides of the triangle.
Prove that the area of the equilateral triangle drawn on the hypotenuse of a right angled triangle is equal to the sum of the areas of the equilateral triangles drawn on the other two sides of the triangle. Hence proved Question 5. RD Sharma Class 12 Solutions. Watch Youtube Videos.
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