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Boats and Streams Formulas | PrepInsta. In water, the direction along the stream is called downstream. 2. Upstream. In water, the direction against the stream is called upstream. Derivation of formula 8 (boats and streams) Derivation of formula 7 (boats and streams) Let time taken to travel upstream $=t_2$ hr. Sep 13, �� Formula 1: If the ratio of downstream and upstream speeds is D: U, then ratio of time taken will be U: D. Question: A boat running upstream takes 8 hours 48 minutes to cover a certain distance, while it takes 4 hours to cover the same distance running downstream. What is the Boat And Stream Formula In Bengali Full ratio between the speed of the boat and speed of the water current respectively? Formula Boats is expanding the boundaries of the crossover bowrider with the debut of the company�s flagship, the Super Sport Crossover. She combines an open bow and deck layout with a full cabin to create an inviting day boat with overnighting capabilities and offshore cruising. She is powered by quadruple Mercury V12 L Verado hp outboards and is essentially a watersports-oriented express cruiser. With a highly polished painted hull, she will be immediately recognized wherever she goes. Boats & Streams is one of the favorite areas of Boats And Streams Aptitude Formulas Zip examiners. Questions from this area appear in a significant proportion in the quant section of almost all the competitive exams. Before starting with the questions, go through the basic concepts of the topic.� A man can row a boat in still water at u km/hr. A stream is flowing at v km/hr and it take t hrs more in upstream than to go downstream for the same distance, then the distance is calculated by = (u2 � v2)t/2v km. A man rows a certain distance downstream in t1 hrs and returns the same distance upstream in t2 hrs. If the speed of the stream is v km/hr, then the speed of the man in still water will be calculated by. A man can row a boat in still water at u km/hr. Derivation of formula 8 (boats and streams). Let the speed of a man in still water = $x$ km/hr speed of the stream = $y$ km/hr. Assume he travels a distance $d$ km upstream and come back the same distance downstream, and total time taken = $t$ hours. Speed downstream $=(x+y)$ Speed upstream $=(x-y)$. Time taken to travel upstream $=\dfrac{d}{x-y}$ Time taken to travel downstream $=\dfrac{d}{x+y}$. Total time $=t$ $\dfrac{d}{x-y}+\dfrac{d}{x+y}=t\\ d(x+y)+d(x-y)=t(x+y)(x-y)\\ 2dx=t(x+y)(x-y)\\ 2dx=t(x^2-y^2)\\ d=\dfrac{t(x^2-y^2). }{2x}$.
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