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UPSTREAM - Intermediate B2 �������� | ���������� ���������� | English | ��������� Speed of the steamer in downstream = x +2 Speed of the steamer in upstream = x � 2 So time = Distance / speed Distance = speed x time D = (x +2) 4 D = (x � 2) 5 As the distance between the port is same. 4(x +2) = 5(x -2) 4x + 8 = 5x x = X = 18 Speed of the the steamer in still water = 18 m/h. Jun 12, �� If it takes �t� hours more to go to a point upstream than downstream for the same distance, the formula for distance will be: Distance = {(u 2-v 2) ? t} / 2v, where �u� is the speed of the boat in still water and �v� is the speed of the stream. Oct 14, �� We can set up two equations, one for the upstream and one for the downstream: d = rt and D = RT. The downstream rate will have an overall rate faster than the boat in still water since the flow of the water speeds them up: R = b + w (boat and water rate) Then the upstream rate is the same except the water rate slows down the boat, so: r = b - w.
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Forums New posts Search forums. What's new New posts Latest activity. Log in Register. Search titles only. Search Advanced search�. New posts. Search forums. Log in. For a better experience, please enable JavaScript in your browser before proceeding. Intermediate Algebra: A boat goes mi downstream in the.

Thread starter Helen Start date Nov 10, Helen Junior Member. Joined Oct 28, Messages I need help in putting this together so that I can solve it. A boat goes miles downstream in the same time it can go miles upstream. The speed of the current is 7 miles per hour. Find the speed of the boat in still water. Please just start me out. TchrWill Full Member. Joined Jul 7, Messages Why is t the same for both cyclists? Because I am measuring from the time they both started to the time they meet somewhere in the middle.

And how did I get " d " Upstream Downstream Algebra Word Problems Activation and " 45 � d " for the distances? Because once I'd assigned the slow guy as having covered d miles, that left 45 � d miles for the fast guy to cover: the two guys together covered the whole 45 miles. Since these distances add up to 45 , I will add the distance expressions and set equal to the given total:. Solve for t. I have used " b " to indicate the boat's speed.

Because I actually have two speeds combined into one on each trip. The boat has a certain speed the "speed in calm water" that I'm looking for; this is the speed that registers on the speedometer , and the water has a certain speed this is the "current".

When the boat is going with the current, the water's speed is added to the boat's speed. This makes sense, if you think about it: even if you cut the engine, the boat would still be moving, because the water would be carrying it downstream. When the boat is going against the current, the water's speed is subtracted from the boat's speed.

This makes sense, too: if the water is going fast enough, the boat will still be going downstream a "negative" speed, because the boat would be going backwards at this point , because the water is more powerful than the boat. Think of a boat in a cartoon heading toward a waterfall. The guy paddles like crazy, but he still goes over the edge.

Solve for b. Then back-solve for d.

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