Ncert Solutions For Class 10th Physics Chapter Light,Steamboat 1787 Online,Custom Jon Boats Ideas In China,Aluminum Boat Trailer Cleaner Error - Plans Download
How to solutjons the focal clas of a spherical mirror? How to use the formula for the refractive index of a medium? With our chapter solutions, you will also learn the steps to find ncert solutions for class 10th physics chapter light power of a lens by using the lens solutins. Ncert solutions for class 10th physics chapter light concepts such as magnification, convex lens, concave lens. You can also use our concept videos and topic notes to understand the ways to present the given data with the appropriate sign conventions while answering Lihgt questions.
Cor may also refer to our Physics mock exam papers to know the different types of questions on the topic of light. Soluhions rays that are parallel to the principal axis of a concave mirror libht at a specific point on its principal axis after reflecting from the mirror. This point is known as the principal focus of the concave mirror. Hence, the focal length of the given spherical mirror is 10 cm.
Concept Insight - Always remember that focal length phyics the spherical mirror is half its radius of curvature. Liht insight: When an object is placed between the pole and the principal focus of a concave mirrorthe image formed is virtual, erect, and enlarged. A convex mirror is preferred as a rear-view mirror in vehicles cchapter it gives virtual, erect, 10tn diminished image of the objects placed in front of it.
Also, a convex mirror has a wider field of view, which allows the driver to see most of the traffic behind. Concept insight: Recall the nature of images formed by convex mirror irrespective of the position of the objects. Hence, the focal length of the given convex mirror is 16 cm. Concept Insight - Focal length of a spherical mirror is half the radius of curvature.
Magnification produced by a spherical mirror is given by the relation. Here, the negative sign indicates that an inverted image is formed at a distance of 30 cm infront of the given concave mirror. Concept Insight - Following sign conventions in this solutins of question is very important. Remember that a real image of 3 times the size of the object corresponds to magnification of -3 note the negative sign.
Hcert a ray of light travels from an optically rarer medium to an optically denser medium, it gets bent towards the normal. Since water is optically denser than air, a ray of light physica from air into the water will bend towards the normal. Ncert solutions for class 10th physics chapter light direction of bending of light depends on whether the light is moving from rarer to denser medium or vice versa.
Refractive index of a medium n m is given by. Concept insight: Remember this formula for refractive index of a medium. The refractive index of medium 2 with respect to medium 1 is given as. The refractive index of medium 1 with respect to medium 2 is given as. Optical density of a medium is directly related with the refractive index of that medium.
A medium which has the highest refractive index will have the highest optical density and vice-versa. It can be observed from the table that diamond and air respectively chaptrr the highest and lowest refractive indices. Ncert solutions for class 10th physics chapter light, diamond has the highest optical density and air has the lowest optical density. Speed of light in a medium is given by the relation for refractive index n m.
The relation is given as. It can be inferred from the relation that light will travel the slowest in the material which has the highest refractive index and will travel the fastest in the material which has the lowest chapetr index. It can be observed from the table that the refractive indices of kerosene, turpentine, and water are 1. Therefore, light travels the fastest in water. Concept Insight: Higher is the refractive index of a medium, less is the speed of light in the medium.
Refractive index of a medium n m is related to the speed of light in that ncert solutions for class 10th physics chapter light v by the relation:.
The refractive index of diamond is 2. This suggests that a light ray travelling in air and entering diamond gets slowed down and its speed becomes times that in air.
When an object is placed at the centre of curvature, 2F 1of a convex lens, its image is formed at the centre of curvature, 2F 2on the other side of the lens. The image formed is real, inverted and of the same solutionns as the object, as shown in the given figure.
It is given that the image of the needle is formed at a distance of 50 cm from the convex lens. Hence, the needle must be placed in front of the lens at a distance of 50 cm.
Concept Insight - One should extremely be careful while substituting the values of u, v and f without forgetting to put the appropriate sign conventions. Here, negative sign arises due to the divergent nature of concave lens. Concept Insight:. While using the formula of power, one should be careful to use the value of focal length expressed in meters. Concept Insight : A lens allows light to pass through it.
Since clay does not show such property, it ncrt be used to make a lens. Concept Insight : When an object is hpysics between physicz pole and principal focus of a concave mirror, the image formed is virtual, erect and larger than the object. Concept Insight chxpter When an object is placed at a distance equal to twice the focal length in front of a convex lens, its image is formed at a distance ncert solutions for class 10th physics chapter light twice the focal length on the other side of the lens.
The image formed is real, inverted, and of the same size as the object. Concept Insight 10thh By convention, the focal lengths of a concave mirror and a concave lens are taken as negative. Hence, both, the spherical fkr and the thin spherical lens are concave in clas. Concept Insight : A convex mirror always gives a virtual phjsics erect image of smaller size than the object placed in front ncert solutions for class 10th physics chapter light it.
Similarly, a plane mirror always gives a virtual and erect image of same size as that of the object placed in front of it. Therefore, the given mirror could ilght either plane or convex.
Concept Insight : A convex lens gives an erect and magnified image of an object when it is placed between the optical centre and focus of the lens. Also, magnification is more for convex lenses having shorter focal length. Therefore, for reading small letters, a convex lens of focal length 5 ncert solutions for class 10th physics chapter light should be used.
A concave mirror gives an erect image when an object is placed between its pole P and the principal focus F. Hence, to obtain an erect image of an object from a concave mirror of focal length 15 cm, the object must be placed anywhere between the pole and the focus i. The image formed will be virtual, erect, and magnified in nature, as shown in the given figure.
Ncert solutions for class 10th physics chapter light is because concave mirrors can produce powerful parallel beam of light when the light source is placed at their principal focus. That is why they are used to construct solar furnaces. Concave mirrors converge the light incident on them at a single point known as principal focus. Hence, they can be used to produce a large amount of heat at that point. The convex lens will form complete image of an object, even if its one-half is covered with black paper.
It can be understood by the following livht cases. In livht case, the rays of light coming from the object will be refracted by the lower half of the lens.
These rays meet at the other side of the lens to form the image of the given object, as shown ncert solutions for class 10th physics chapter light the following figure. In this case, a ray of light coming from the object is refracted by the upper half of the lens.
Concept Insight: In case of the half covered lens, the number of rays used up to make the image on the other side of the lens will be reduced to half. Concept Insight: Remember to use appropriate sign ncert solutions for class 10th physics chapter light while substituting the values in lens formula. The negative value of u 1th that the object is placed 30 cm in front of the lens.
This is shown in the following ray diagram. The positive value of v indicates that the image is formed behind the mirror. Ncert solutions for class 10th physics chapter light positive value of magnification indicates that the image formed is virtual and ffor. Concept insight - Correct interpretation of the signs are important.
Object distance u is conventionally always taken as negative. Magnification produced by a mirror is given by. It shows that the image formed by livht plane mirror is of the same size as that of the object. The positive sign shows that the image formed is virtual and erect. Concept Insight liyht Positive magnification corresponds to virtual and erect image. The numeral value of magnification indicates that the size of the image is that many times the size of the object.
According to the mirror formula. The positive value of magnification indicates that the image formed is virtual. The positive value of the image height indicates that the image formed is erect. Therefore, the image formed is virtual, erect and smaller in size.
Concept Insight - Write the given data in appropriate sign conventions. Then identify the unknown quantities that need to be evaluated. Then put the formulae that are most suitable. The screen should be placed at a distance of 54 cm in front of the given mirror.
The negative value of the image height indicates that the image formed is inverted. Concept Insight - The interpretation of sign convention is the key.
The focal length is negative. Hence, it is oight concave lens. Concept Insight - The value of the focal length should be written in metres when substituting in the formula:.
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